In the diagram above, ABC is a right triangle (with right angle at C), and the segments AD, DF, FE, EC, and CB are all of equal length. What is the size of angle A?
U don't have any measurements on the triangle except for the 90 degree angle?? What about the sides...they r equal length but do u have the measurement to them...I will look at it and see if I can figure it out.
it is 18.. i wrote it out on paper and i'll scan but here's my explanation to my friend who was also working on it.
patrick w is god: i did all the angles =
patrick w is god: that were isoceles dealies right
gene: yea
patrick w is god: so i set b and ceb as x
patrick w is god: so ecb is 180-2x
patrick w is god: so fce is 90-(180-2x)
patrick w is god: so it is -90+2x
gene: yea
patrick w is god: so efc is also -90-2x
patrick w is god: +2x
patrick w is god: no -
patrick w is god: so fec is 180-2(-90+2x)
patrick w is god: 360-4x
patrick w is god: def is 180-(360-4x)-(x)
patrick w is god: so it is -180+3x
patrick w is god: so dfe is 180-2(-180+3x)
patrick w is god: 540-6x
patrick w is god: so dfa is 180-(540-6x)-(-90+2x)
patrick w is god: that is -270+4x
patrick w is god: so A is -270-4x as well
patrick w is god: so 180=-270+4x + x + 90
patrick w is god: 180=-180+5x
patrick w is god: 360=5x
patrick w is god: x=72
A=-270+4(72)=18
A=18