|
The area of the square is 1300 square inches.
Like most geometry problems, there are a lot of ways to do this one. Here is one short and elegant solution which makes use of the formula for the area of a parallelogram.
Label x, y, and z as in the figure. Now the area of a paralellogram is its height times its base width. The height of the yellow parallelogram is x and its base width is y. So, its area is xy. But this must also be one-third of the entire square, so
xy = (1/3)x2,
or
y = (1/3)x.
This means that the purple piece is a right triangle with legs of length x and x - y = (2/3)x and hypotenuse of length z. So, using the Pythagorean Theorem,
z2 = x2 + (4/9)x2 = (13/9)x2,
so
z = (1/3)sqrt(13)x.
Finally, we can look again at the yellow parallelogram, but this time turn our heads to the side just a little bit. Its "height" is now 10 and its "base width" is z = (1/3)sqrt(13)x, so its area (one-third the total area of the square) must be the product of these two numbers, so
(1/3)x2 = [10][(1/3)sqrt(13)x],
or
x = 10sqrt(13).
The area of the whole square is then
x2 = (10sqrt(13))2 = 1300 square inches.
|