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Old 04-09-2002, 10:01 PM   #4 (permalink)
kakyoin
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Join Date: Oct 2001
Location: Austin, Texas
Posts: 39
kakyoin is on a distinguished road
I just re-verified it, it is the length of the vector
An advanced way of saying that:
||x|| = sqrt (x.x) [square root of x dot x]

quoted from a dusty linear algebra book

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